Specific heat capacity · Grade 12

In Grade 12 you learn: mixing hot and cold.

The specific heat capacity of a material is the energy needed to warm 1 kg of it by 1°C. Water needs a lot, 4,200 J for each kilogram and degree, while metals need much less. The energy to change the temperature of anything is E = mcΔT, and you can measure c by heating a block with an electric heater.

Key facts

  • To measure c, heat a block with an electric heater: c = E ÷ (mΔT). Energy lost to the surroundings makes the result too high.
  • When hot and cold mix: energy lost by the hot = energy gained by the cold.

Worked examples

Example 1

A 1.5 kW heater warms a 2.0 kg aluminum block for 2 minutes. The temperature rises by 90°C. Find c for aluminum (assume no losses).

Answer: 1,000 J/(kg °C)

Example 2

A 50 W heater warms a 1.0 kg aluminum block for 300 s, and its temperature rises by 16°C. Find the specific heat capacity it measures. Why is it more than the true value, 900 J/kg°C?

Answer: about 940 J/kg°C; some energy heats the surroundings instead of the block

Example 3

A student measures the specific heat capacity of aluminum as 1,050 J/kg °C, higher than the true value of 900. What is the most likely reason?

Answer: energy was lost to the surroundings, so more energy was measured than actually heated the block

Example 4

0.5 kg of water at 83°C is mixed with 0.7 kg of water at 16°C in an insulated jug. What is the final temperature, to 1 decimal place?

Answer: 43.9°C

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