Electric fields
An electric field is the region around a charge where other charges feel a force. Field strength E is the force on each coulomb of charge placed there. Fields can be drawn with lines: radial around a point charge, and uniform (parallel and evenly spaced) between two charged plates – the arrangement used in inkjet printers, cathode-ray tubes and particle accelerators.
Key facts
- E = F ÷ q (N/C), so F = qE.
- Point charge: E = kQ ÷ r², with k = 9.0 × 10⁹ N m²/C².
- Between parallel plates: E = V ÷ d (V/m, the same as N/C).
- Field lines point from + to −, never cross, and are closer where the field is stronger.
- Work done on a charge moved through a p.d.: W = qV; an electron accelerated through V gains eV of kinetic energy.
- Fields from several charges add as vectors.
Worked examples
Example 1
Find the field strength 20 cm from a +8 nC point charge.
- Substitute E = 9.0 × 10⁹ × 8 × 10⁻⁹ ÷ 0.20²
- Work it out E = 72 ÷ 0.04 = 1800 N/C
- The charge is positive, so the field points away from it.
Answer: 1800 N/C, pointing away from the charge
Example 2
Plates 4 mm apart have 200 V between them. Find the field strength and the force on a 3 nC droplet between them.
- E = V ÷ d E = 200 ÷ 0.004 = 50 000 V/m
- F = qE F = 3 × 10⁻⁹ × 50 000 = 1.5 × 10⁻⁴ N
Answer: 50 000 V/m; 1.5 × 10⁻⁴ N
Example 3
Charges of +4 nC and −4 nC are 20 cm apart. Find the field at the midpoint.
- Each is 10 cm away E = 9.0 × 10⁹ × 4 × 10⁻⁹ ÷ 0.10² = 3600 N/C
- From +: away from +, i.e. towards −. From −: towards −. Same direction.
- Total 3600 + 3600 = 7200 N/C towards the negative charge
Answer: 7200 N/C towards the negative charge