The Doppler effect
When a source of waves moves towards you, the waves get squashed together so you receive a higher frequency; when it moves away they are stretched and the frequency drops. You hear it as a siren’s pitch falls as it passes. The same effect in light – red shift and blue shift – tells astronomers how fast stars and galaxies are moving.
Key facts
- Source approaching: higher observed frequency (shorter wavelength). Receding: lower frequency.
- Source moving, listener still: f_L = v f_s ÷ (v ∓ v_s) (− when approaching, + when receding).
- Listener moving, source still: f_L = (v ± v_L) f_s ÷ v (+ when approaching).
- The speed of the sound itself does not change; only the received frequency and wavelength do.
- Light: red shift z = Δλ ÷ λ ≈ v ÷ c for speeds much less than c.
- Uses: speed cameras (radar), measuring blood flow with ultrasound, finding exoplanets and galaxy speeds.
Worked examples
Example 1
An ambulance siren of 700 Hz approaches at 25 m/s. Speed of sound 340 m/s. What frequency does a pedestrian hear? And after it passes?
- Approaching f_L = 340 × 700 ÷ (340 − 25) = 755.6 Hz
- Receding f_L = 340 × 700 ÷ (340 + 25) = 652.1 Hz
Answer: 755.6 Hz approaching; 652.1 Hz receding
Example 2
A car horn is 500 Hz. A stationary listener hears 530 Hz as it approaches. How fast is the car? (v = 340 m/s)
- 530 = 340 × 500 ÷ (340 − v_s) 340 − v_s = 170 000 ÷ 530 = 320.8
- So v_s = 340 − 320.8 = 19.2 m/s
Answer: about 19.2 m/s
Example 3
A hydrogen line emitted at 656.3 nm is observed at 662.9 nm from a galaxy. How fast is it moving, and which way?
- Δλ 662.9 − 656.3 = 6.6 nm
- z = Δλ ÷ λ z = 6.6 ÷ 656.3 = 0.0101
- v = zc v = 0.0101 × 3.0 × 10⁸ ≈ 3.0 × 10⁶ m/s
- Longer wavelength: red shift, so it is receding.
Answer: about 3.0 × 10⁶ m/s, away from us