Atom economy · Grade 12

In Grade 12 you get fluent with: atom economy; reactions with an atom economy of 100%; choosing a process: yield, atom economy and waste.

Atom economy looks at the reaction itself: what percentage of the mass of all the reactants ends up in the product you want. It comes straight from the balanced equation. A reaction with only one product wastes nothing, while one with many by-products has a low atom economy unless the by-products can be used.

Key facts

  • Atom economy = Mᵣ of the useful product ÷ total Mᵣ of all the reactants × 100, using the numbers from the balanced equation.
  • A reaction with only one product, such as an addition reaction, has an atom economy of 100%.
  • A low atom economy means a lot of waste, unless the other products can be used or sold.
  • To choose a way of making a product, compare the yield, the atom economy, the rate, the equilibrium position and the usefulness of any by-products.

Worked examples

Example 1

Find the atom economy for making calcium oxide by heating calcium carbonate. CaCO3 → CaO + CO2 (Aᵣ: Ca = 40, C = 12, O = 16)

Answer: 56%

Example 2

N2 + 3H2 → 2NH3. What is the atom economy for making chem NH3, to 1 decimal place? (Aᵣ: N = 14, H = 1)

Answer: 100%

Example 3

Which kind of reaction always has an atom economy of 100%?

Answer: a reaction with only one product, such as an addition reaction

Example 4

What does a high atom economy mean?

Answer: most of the atoms in the reactants end up in the useful product

Example 5

2Al2O3 → 4Al + 3O2. What is the atom economy for making chem Al, to 1 decimal place? (Aᵣ: Al = 27, O = 16)

Answer: 52.9%

Example 6

Ethanol can be made by fermentation, C6H12O6 → 2C2H5OH + 2CO2, or by adding steam to ethene, C2H4 + H2O → C2H5OH. Compare their atom economies. (Aᵣ: C = 12, H = 1, O = 16)

Answer: fermentation 51.1%; from ethene 100%

Example 7

A process has a high yield but a low atom economy. Why might a company still be concerned?

Answer: it makes a lot of waste products that must be dealt with

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